Leetcode/Lintcode
- Finish Senior Dynamic Programming
- Finished two pointers, very elegant algorithm, the key point is the prove of correctness of no return of j. And this leads from O(n^2) to O(n)!
Fight for your dream: first step, finish 9chap, Algs4/Stanford, and Leet/Lintcode
Leetcode/Lintcode
Fight for your dream: first step, finish 9chap, Algs4/Stanford, and Leet/Lintcode
MIT License