thekoc / flask-pymongo

PyMongo support for Flask applications

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Flask-PyMongo

PyMongo support for Flask applications

Quickstart

from flask import Flask, render_template
from flask_pymongo import PyMongo

app = Flask(__name__)
app.config["MONGO_URI"] = "mongodb://localhost:27017/myDatabase"
mongo = PyMongo(app)

@app.route('/')
def home_page():
    online_users = mongo.db.users.find({'online': True})
    return render_template('index.html', online_users=online_users)

More Info

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PyMongo support for Flask applications

License:BSD 2-Clause "Simplified" License


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Language:Python 100.0%