qicaisheng / guess-number

需求

实现猜数字的游戏。游戏有四个格子，每个格子有一个0到9的数字，任意两个格子的数字都不一样。 你有6次猜测的机会，如果猜对则获胜，否则失败。 每次猜测时需依序输入4个数字，程序会根据猜测的情况给出xAxB的反馈，A前面的数字代表位置和数字都对的个数，B前面的数字代表数字对但是位置不对的个数。

例如：答案是1 2 3 4， 那么对于不同的输入，有如下的输出

Input Output Instruction

1 5 6 7 1A0B 1 correct 2 4 7 8 0A2B 2 and 4 wrong position 0 3 2 4 1A2B 4 correct，2 and 3 wrong position 5 6 7 8 0A0B all wrong 4 3 2 1 0A4B 4 numbers position wrong 1 2 3 4 4A0B win, all correct 1 1 2 3 Wrong Input，Input again 1 2 Wrong Input，Input again 答案在游戏开始时随机生成。输入只有6次机会，在每次猜测时，程序应给出当前猜测的结果，以及之前所有猜测的数字和结果以供玩家参考。

Tasking

guess number

• given Game with answer 1 2 3 4, when input 1 5 6 7, then output 1A0B
• given Game with answer 1 2 3 4, when input 2 4 7 8, then output 0A2B
• given Game with answer 1 2 3 4, when input 0 3 2 4, then output 1A2B
• given Game with answer 1 2 3 4, when input 1 2 3 4, then output 4A0B

validate input

• given Game with answer 1 2 3 4, when input 1 1 2 3, then output Wrong Input，Input again
• given Game with answer 1 2 3 4, when input 1 2, then output Wrong Input，Input again

end game

• give Game with answer 1 2 3 4, when input 1 2 3 4, then success
• give Game with answer 1 2 3 4 and 6 chances left to guess, when input 1 2 5 8, then user can try again, the chances left will be 5
• give Game with answer 1 2 3 4 and 1 chances left to guess, when input 1 2 5 8, then failed

guess history

• given Game with answer 1 2 3 4 and 1 not succeed guess with input 1 5 6 7, when input 2 4 7 8, then output 0A2B and history 1 5 6 7 1A0B\n

generate answer

PMD

• Use Gradle
  • run ./gradlew clean pmdMain
• Use Maven
  • run ./mvnw clean pmd:pmd