nanashiki / SegueAddition

Easily way to write perfromSegueWithIdentifier.

SegueAddition

Easily way to write perfromSegueWithIdentifier.

Usage

You can use performSegue in UIViewController subclass.
performSegue work similar for performSegueWithIdentifier.
But, performSegue is cooler compared with using performSegueWithIdentifier.

let customString = "CustomString"
performSegue("SegueIdentfiier") { segue in
  guard let toViewController = segue.destinationViewController as? CustomViewController else {
    fatalError()
  }
  toViewController.string = customString
}

same this

...
let customString = "CustomString"
performSegueWithIdentifier("SegueIdentfiier", sender: customString)
...

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
  guard let toViewController = segue.destinationViewController as? CustomViewController,
            customString = sender as? String
        where segue.identifier == "SegueIdentfiier"
        else {
            fatalError()
        }
        toViewController.string = customString
}

If you use performSegue, it isn't necessary to write override func prepareForSegue method. Because you can write closure in performSegue, what done on prepareForSegue!

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    fatalError("Do not call")    
}

Couldn't call prepareForSegue passed performSegueWithIdentifier? No, it's possible to use performSegueWithIdentifier method same way.

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    print("Call this one") // Print in console "Call this one"
}

...
performSegueWithIdentifier("SegueIdentifier", sender: nil)
...

Only to use performSegue case, that not call prepareForSegue.

LICENSE

SegueAddition is released under the MIT license. See LICENSE for details.