michelribeiro / javascript_exercises

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Intersection

var a1 = [1,2,4,5,7]
var a2 = [2,3,4,7]

var intersection = a1.filter(i => a2.includes(i));
console.log(intersection); // result [2,4,7]

Palindrome

var isPalindrome = function(x) {
   return x == String(x).split("").reverse().join("")
};
isPalindrome(121) // true
isPalindrome(122) // false

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