jasonmorganson / mealme

MealMe Code inteview

Instructions

[45 minutes] Create a function that determines whether a store is currently open, given a dictionary representing it’s open hours for days of the week. Note that the closing time is exclusive, so if a store closes at 2100, then it is no longer open starting at 2100.

Notes:

• is_open(current_time: int, day: int, hours: dict) -> bool
• Input Arguments
  • current_time: range = [0, 2400)
  • day
    • range = [0, 6]
    • 0 is Sunday
  • hours
    • weekday keys
      • range = [0, 6]
      • 0 is Sunday, 6 is Saturday
    • open: range = [0, 2400)
    • close: range = [0, 2400)
    • open != close
    • The following can be true: close < open

Sample hours input:

// 0 is sunday
hours = {
0: [{"open": 800, "close": 1500}, {"open": 1700, "close": 200}],
2: [{"open": 800, "close": 1200}, {"open": 1500, "close": 2100}],
3: [{"open": 800, "close": 2100}],
4: [{"open": 800, "close": 0}],
5: [{"open": 800, "close": 2100}],
6: [{"open": 800, "close": 1300}, {"open": 1700, "close": 200}]
}

Test cases

1. is_open(current_time=800, day=0) Should return: True Returns: True

2. is_open(current_time=1800, day=0) Should return: True Returns: True

3. is_open(current_time=1600, day=0) Should return: False Returns: False

4. is_open(current_time=100, day=1) Should return: True Returns: False

Run & Test

python is_open.py