= django-jqgrid = django-jqgrid aims to make integrating full support for jqgrid as simple as defining which models you want exposed, while still supporting the more advanced features. After unexpected interest, I have decided to provide an early release in the form as a utility class. This release is not stable or intented for production use. I will be cleaning up, restructuring (to a more flexible classed generic handler), and adding documentation/examples soon. Until then, you have been warned! == Prerequisites == * [http://code.google.com/p/dojango/source/browse/trunk/dojango/util/__init__.py#97 json_encode] * [http://www.jquery.com jQuery 1.3+] * [http://www.trirand.com/blog/?page_id=6 jqGrid 3.5+] == Example == 1. First define your grid somewhere (e.g., grids.py). Only a model or queryset and a url are required. {{{ class ExampleGrid(JqGrid): model = SomeFancyModel # could also be a queryset fields = ['id', 'name', 'desc'] # optional url = reverse('grid_handler') caption = 'My First Grid' # optional colmodel_overrides = { 'id': { 'editable': False, 'width':10 }, } }}} 2. Create views to handle requests. {{{ def grid_handler(request): # handles pagination, sorting and searching grid = ExampleGrid() return HttpResponse(grid.get_json(request), mimetype="application/json") def grid_config(request): # build a config suitable to pass to jqgrid constructor grid = ExampleGrid() return HttpResponse(grid.get_config(), mimetype="application/json") }}} 3. Define urls for those views. {{{ url(r'^examplegrid/$', grid_handler, name='grid_handler'), url(r'^examplegrid/cfg/$', grid_config, name='grid_config'), }}} 4. Configure jgrid to use the defined urls. {{{ $(function () { $.getJSON("{% url grid_config %}", function(data){ $("#mygrid") .jqGrid(data) .navGrid('#pager', {add: false, edit: false, del: false, view: true}, {}, // edit options {}, // add options {}, // del options { multipleSearch:true, closeOnEscape:true }, // search options { jqModal:false, closeOnEscape:true} // view options ); }); }); }}}