persistentBugger
Write a function, persistence, that takes in a positive parameter num and returns its multiplicative persistence, which is the number of times you must multiply the digits in num until you reach a single digit. For example (Input --> Output): 39 --> 3 (because 39 = 27, 27 = 14, 14 = 4 and 4 has only one digit) 999 --> 4 (because 999 = 729, 729 = 126, 126 = 12, and finally 12 = 2) 4 --> 0 (because 4 is already a one-digit number)
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