This repository contains a Java solution for calculating the minimum number of flips required to make (a OR b) == c, where a, b, and c are positive numbers.
Given three positive numbers a, b, and c, the goal is to determine the minimum number of flips required in some bits of a and b to make (a OR b) == c (bitwise OR operation). A flip operation consists of changing any single bit 1 to 0 or changing the bit 0 to 1 in their binary representation.
The provided Java solution utilizes bitwise operations to extract the least significant bit of a, b, and c in each iteration. The logic of the solution can be summarized as follows:
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Initialize a variable
flipsto keep track of the number of flips required. -
Start a loop that continues until all bits of
a,b, andchave been processed. -
Extract the least significant bit of
a,b, andcusing the bitwise AND operator (&). -
Check the value of
bitC:- If
bitCis 0, addbitA + bitBto theflipscount since the corresponding bit incis 0 and we need to flipaand/orbif either of them has a corresponding bit set to 1. - If
bitCis 1, add 1 to theflipscount only if bothbitAandbitBare 0 since the corresponding bit incis 1 and we only need to flipaandbif both of them have a corresponding bit set to 0.
- If
-
Right-shift
a,b, andcby 1 bit to process the next least significant bit. -
Repeat the loop until all bits of
a,b, andchave been processed. -
Return the total number of flips stored in the
flipsvariable.
The minFlips method provided in the Solution class accepts three positive integer values a, b, and c as input and returns the minimum number of flips required to make (a OR b) == c. To use this method, follow these steps:
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Compile the Java code using a Java compiler or IDE of your choice.
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Call the
minFlipsmethod with the desired values fora,b, andc. -
The method will return the minimum number of flips required.
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You can customize the
mainmethod in the code to test the solution with different input values.
Feel free to explore the code and modify it as needed.