PatrickA94 / python-pathfinding

Pathfinding algorithms based on Pathfinding.JS

python-pathfinding

Pathfinding algorithms based on Pathfinding.JS for python 2 and 3 (just A* and dijkstra for now)

usage example

A simple usage example to find a path using A*.

1. import the required libraries:

   from pathfinding.core.diagonal_movement import DiagonalMovement
   from pathfinding.core.grid import Grid
   from pathfinding.finder.a_star import AStarFinder

2. Create a map using a 2D-list. 1, True or any value describes an obstacle. 0, False or None descibes a field that can be walked on. In this example we like the algorithm to create a path from the upper left to the bottom right. To make it not to easy for the algorithm we added an obstacle in the middle, so it can not use the direct way. Feel free to create a more complex map

   matrix = [
     [0, 0, 0],
     [0, 1, 0],
     [0, 0, 0]
   ]

3. we create a new grid from this map representation. This will create Node instances for every element of our map. It will also set the size of the map. We assume that your map is a square, so the size height is defined by the length of the outer list and the width by the length of the first list inside it.

   grid = Grid(matrix=matrix)

4. we get the start (top-left) and endpoint (bottom-right) from the map:

   start = grid.node(0, 0)
   end = grid.node(2, 2)

5. create a new instance of our finder and let it do its work. We allow diagonal movement. The find_path function does not only return you the path from the start to the end point it also returns the number of times the algorithm needed to be called until a way was found.

   finder = AStarFinder(diagonal_movement=DiagonalMovement.always)
   path, runs = finder.find_path(start, end, grid)

6. thats it. We found a way. Now we can print the result (or do something else with it). Note that the start and end points are part of the path.

   print('operations:', runs, 'path length:', len(path))
   print(grid.grid_str(path=path, start=start, end=end))

   The result should look like this:

   ('operations:', 5, 'path length:', 4)
   
   +---+
   |sx |
   | #x|
   |  e|
   +---+
   

   You can ignore the +, - and | characters, they just show the border around your map, the blank space is a free field, 's' marks the start, 'e' the end and '#' our obstacle in the middle. You see the path from start to end marked by 'x' characters. We allow horizontal movement, so it is not using the upper-right corner. You can access print(path) to get the specific list of coordinates.

Here The whole example if you just want to copy-and-paste the code and play with it:

from pathfinding.core.diagonal_movement import DiagonalMovement
from pathfinding.core.grid import Grid
from pathfinding.finder.a_star import AStarFinder

matrix = [
  [0, 0, 0],
  [0, 1, 0],
  [0, 0, 0]
]
grid = Grid(matrix=matrix)

start = grid.node(0, 0)
end = grid.node(2, 2)

finder = AStarFinder(diagonal_movement=DiagonalMovement.always)
path, runs = finder.find_path(start, end, grid)

print('operations:', runs, 'path length:', len(path))
print(grid.grid_str(path=path, start=start, end=end))

Take a look at the test/ folder for more examples.