Nurunnajwa12 / Finding-Odd-and-Even-Number

This final assignment target is to find odd and even number by using repetition and else if technique.

Finding Odd and Even House Number

This program should be able to find and display the list of all even,odd and semi-detached house number.

Target

• Display the even house number
• Display the odd house number
• Display the semi-detached house number.

Code Explanation

• We do repetition until the specified number is find.

    System.out.print("\nOdd house number are : ");
         int odd=0;
         for (z=0;z<array.length;z=z+1)

• To find odd number , use array[object name]%2 !=0.
• If the number that calculate by using ampersand with two not equal to zero, the number is odd number
• Eg: 3%2 = 1 , 1 !=0, therefore 3 is odd number. We have satisfied the condition of code above.

if(array[z]% 2 !=0)
            {
                System.out.print(array[z]+" ");
                odd=1;
            }

• The same code applied to even number

if(array[z]%2==0)
             {
                 System.out.print(array[z]+" ");
                 even=1;
             }

• For semi detached house, the house number must belong from 6 until 15

 if (array[z]>=6 && array[z]<=15)
              {
                  System.out.print(array[z]+" ");
                  semi=1;
              }

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