StrideArrays
Use
julia> @time using StrideArrays
5.921865 seconds (12.17 M allocations: 722.046 MiB, 2.96% gc time, 70.89% compilation time)
julia> A = @StrideArray rand(3,4)
3×4 StrideArraysCore.StaticStrideArray{Tuple{StaticInt{3}, StaticInt{4}}, (true, true), Float64, 2, 1, 0, (1, 2), Tuple{StaticInt{8}, StaticInt{24}}, Tuple{StaticInt{1}, StaticInt{1}}, 12} with indices 1:1:3×1:1:4:
0.504925 0.280823 0.578082 0.839807
0.865055 0.762067 0.897201 0.593801
0.485478 0.95566 0.439315 0.771538
julia> B = similar(A);
julia> @benchmark @. $B = log($A)
BenchmarkTools.Trial: 10000 samples with 580 evaluations.
Range (min … max): 197.441 ns … 306.610 ns ┊ GC (min … max): 0.00% … 0.00%
Time (median): 199.200 ns ┊ GC (median): 0.00%
Time (mean ± σ): 200.114 ns ± 2.698 ns ┊ GC (mean ± σ): 0.00% ± 0.00%
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197 ns Histogram: frequency by time 209 ns <
Memory estimate: 0 bytes, allocs estimate: 0.
julia> @benchmark sum(log.($A))
BenchmarkTools.Trial: 10000 samples with 328 evaluations.
Range (min … max): 271.122 ns … 456.610 ns ┊ GC (min … max): 0.00% … 0.00%
Time (median): 272.936 ns ┊ GC (median): 0.00%
Time (mean ± σ): 279.168 ns ± 17.957 ns ┊ GC (mean ± σ): 0.00% ± 0.00%
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271 ns Histogram: log(frequency) by time 343 ns <
Memory estimate: 0 bytes, allocs estimate: 0.