1) Provide a query showing Customers (just their full names, customer ID and country) who are not in the US.
SELECT LastName || ", " || FirstName AS FullName,
CustomerId,
Country
FROM Customer
WHERE Country != 'USA';
2) Provide a query only showing the Customers from Brazil.
SELECT LastName || ", " || FirstName AS FullName,
Country
FROM Customer
WHERE Country = 'Brazil';
3) Provide a query showing the Invoices of customers who are from Brazil. The resultant table should show the customer's full name, Invoice ID, Date of the invoice and billing country.
SELECT c.LastName || ", " || c.FirstName AS FullName,
i.InvoiceId,
i.InvoiceDate,
c.Country
FROM Customer c
INNER JOIN Invoice i
WHERE c.Country = 'Brazil';
4) Provide a query showing only the Employees who are Sales Agents.
SELECT LastName || ", " || FirstName AS FullName
FROM Employee
WHERE Title = 'Sales Support Agent';
5) Provide a query showing a unique list of billing countries from the Invoice table.
<!-- DISTINCT eliminates duplicate records -->
SELECT DISTINCT BillingCountry
FROM Invoice
ORDER BY BillingCountry ASC;
6) Provide a query that shows the invoices associated with each sales agent. The resultant table should include the Sales Agent's full name.
SELECT
e.LastName || ", " || e.FirstName AS FullName,
i.InvoiceId AS InvoiceID
FROM Employee e
INNER JOIN Customer c ON e.EmployeeId = c.SupportRepId
INNER JOIN Invoice i ON c.CustomerId = i.CustomerId
WHERE e.Title = 'Sales Support Agent'
ORDER BY EmployeeId || InvoiceId;
7) Provide a query that shows the Invoice Total, Customer name, Country and Sale Agent name for all invoices and customers.
SELECT
i.InvoiceId,
i.Total,
c.FirstName,
c.LastName,
c.Country,
e.FirstName || " " || e.LastName AS 'Sales Rep'
FROM
Invoice i
INNER JOIN
Customer c ON c.CustomerId = i.CustomerId
INNER JOIN
Employee e ON e.EmployeeId = c.SupportRepId
WHERE
e.Title = 'Sales Support Agent';
8) How many Invoices were there in 2009 and 2011? What are the respective total sales for each of those years?(include both the answers and the queries used to find the answers)
Invoices in 2009: 83
SELECT
COUNT(*)
FROM
Invoice
WHERE
InvoiceDate >= '2009-01-01'
AND
InvoiceDate <= '2009-12-31';
Invoices in 2011: 83
SELECT
COUNT(*)
FROM
Invoice
WHERE
InvoiceDate >= '2011-01-01'
AND
InvoiceDate <= '2011-12-31';
Code to create report of all sales in 2009:
SELECT
*
FROM
Invoice
WHERE
InvoiceDate >= '2009-01-01'
AND
InvoiceDate <= '2009-12-31';
9) Looking at the InvoiceLine table, provide a query that COUNTs the number of line items for Invoice ID 37.
SELECT
COUNT(InvoiceId)
FROM
InvoiceLine
WHERE
InvoiceId = 37;
10) Looking at the InvoiceLine table, provide a query that COUNTs the number of line items for each Invoice. HINT: GROUP BY
SELECT
il.InvoiceId AS 'Invoice ID',
COUNT(InvoiceId) AS 'Total Line Items'
FROM
InvoiceLine il
GROUP BY
InvoiceId;
11) Provide a query that includes the track name with each invoice line item.
SELECT
il.InvoiceId AS 'Invoice ID',
il.InvoiceLineId AS 'Invoice Line ID',
t.Name AS 'Track Title'
FROM
InvoiceLine il
INNER JOIN
Track t ON t.TrackId = il.TrackId;
12) Provide a query that includes the purchased track name AND artist name with each invoice line item.
SELECT
il.InvoiceId AS 'Invoice ID',
il.InvoiceLineId AS 'Invoice Line ID',
t.Name AS 'Track Title',
ar.Name AS 'Artist'
FROM
InvoiceLine il
INNER JOIN
Track t ON t.TrackId = il.TrackId
INNER JOIN
Album al ON al.AlbumId = t.AlbumId
INNER JOIN
Artist ar ON ar.ArtistId = al.ArtistId;
13) Provide a query that shows the # of invoices per country. HINT: GROUP BY
SELECT
c.Country,
COUNT(InvoiceId)
FROM
Customer c
INNER JOIN
Invoice i ON i.CustomerId = c.CustomerId
GROUP BY Country;
14) Provide a query that shows the total number of tracks in each playlist. The Playlist name should be include on the resulant table.
SELECT
pl.PlaylistId,
pl.Name,
COUNT(t.TrackId) AS 'Songs'
FROM
Track t
INNER JOIN
PlaylistTrack plt ON plt.TrackId = t.TrackId
INNER JOIN
Playlist pl ON pl.PlaylistId = plt.PlaylistId
GROUP BY pl.PlaylistId;
15) Provide a query that shows all the Tracks, but displays no IDs. The resultant table should include the Album name, Media type and Genre.
SELECT
t.Name AS 'Track Name',
al.Title AS 'Album Name',
mt.Name AS 'MediaType',
g.Name AS 'Genre'
FROM
Track t
INNER JOIN
Album al ON al.AlbumId = t.AlbumId
INNER JOIN
MediaType mt ON mt.MediaTypeId = t.MediaTypeId
INNER JOIN
Genre g ON g.GenreId = t.GenreId;
16) Provide a query that shows all Invoices but includes the # of invoice line items.
SELECT
i.InvoiceId,
COUNT(il.InvoiceLineId)
FROM
Invoice i
INNER JOIN
InvoiceLine il ON il.InvoiceId = i.InvoiceId
GROUP BY i.InvoiceId;
17) Provide a query that shows total sales made by each sales agent.
SELECT
e.FirstName || " " || e.LastName AS 'Full Name',
SUM(i.Total) AS 'Total Sales'
FROM
Employee e
INNER JOIN
Customer c ON c.SupportRepId = e.EmployeeId
INNER JOIN
Invoice i ON i.CustomerId = c.CustomerId
WHERE e.Title = 'Sales Support Agent'
GROUP BY e.EmployeeId;
18) Which sales agent made the most in sales in 2009? HINT: MAX
SELECT
e.FirstName || " " || e.LastName AS 'Sales Agent',
SUM(i.Total) AS '2009 Total Sales'
FROM
Employee e
INNER JOIN
Customer c ON c.SupportRepId = e.EmployeeId
INNER JOIN
Invoice i ON i.CustomerId = c.CustomerId
WHERE
e.Title = 'Sales Support Agent'
AND
InvoiceDate >= '2009-01-01'
AND
InvoiceDate <= '2009-12-31'
GROUP BY e.EmployeeId
ORDER BY SUM(i.Total)
DESC LIMIT 1;
<!-- Without GROUP BY the sales totals get added together, must use DESC only after an ORDER BY, and LIMIT # limits resultant rows returned -->
19) Which sales agent made the most in sales over all?
SELECT
e.FirstName || " " || e.LastName AS 'Sales Agent',
SUM(i.Total) AS '2009 Total Sales'
FROM
Employee e
INNER JOIN
Customer c ON c.SupportRepId = e.EmployeeId
INNER JOIN
Invoice i ON i.CustomerId = c.CustomerId
WHERE
e.Title = 'Sales Support Agent'
AND
InvoiceDate >= '2009-01-01'
GROUP BY e.EmployeeId
ORDER BY SUM(i.Total)
DESC LIMIT 1;
20) Provide a query that shows the # of customers assigned to each sales agent.
SELECT
e.FirstName || " " || e.LastName AS 'Sales Agent',
COUNT(c.SupportRepId) AS AssignedCustomers
FROM
Employee e
INNER JOIN
Customer c ON c.SupportRepId = e.EmployeeId
WHERE
e.Title = 'Sales Support Agent'
GROUP BY e.EmployeeId
ORDER BY AssignedCustomers
DESC LIMIT 1;
21) Provide a query that shows the total sales per country. Which country's customers spent the most?
SELECT
c.Country,
SUM(i.Total) AS TotalSales
FROM
Customer c
INNER JOIN
Invoice i ON c.CustomerId = i.CustomerId
GROUP BY c.Country
ORDER BY TotalSales
DESC;
22) Provide a query that shows the most purchased track of 2013.
SELECT
t.Name AS TrackName,
COUNT(il.TrackId) AS 'MostPurchaedof2013'
FROM
InvoiceLine il
INNER JOIN
Invoice i ON il.InvoiceId = i.InvoiceId
INNER JOIN
Track t ON t.TrackId = il.TrackId
WHERE
i.InvoiceDate >= '2013-01-01'
AND
i.InvoiceDate <= '2013-12-31'
GROUP BY t.Name
ORDER BY COUNT(il.TrackId)
DESC LIMIT 9;
23) Provide a query that shows the top 5 most purchased tracks over all.
SELECT
t.Name AS TrackName,
COUNT(il.TrackId) AS 'TOP 5 TRACKS EVER!!!'
FROM
InvoiceLine il
INNER JOIN
Invoice i ON il.InvoiceId = i.InvoiceId
INNER JOIN
Track t ON t.TrackId = il.TrackId
GROUP BY t.Name
ORDER BY COUNT(il.TrackId)
DESC LIMIT 5;
24) Provide a query that shows the top 3 best selling artists.
SELECT
a.Name AS Artist,
COUNT(a.ArtistId) AS 'TOP 3 ARTISTS EVER!!!'
FROM
InvoiceLine il
INNER JOIN
Track t ON t.TrackId = il.TrackId
INNER JOIN
Album al ON al.AlbumId = t.AlbumId
INNER JOIN
Artist a ON a.ArtistId = al.ArtistId
GROUP BY a.Name
ORDER BY COUNT(a.ArtistId)
DESC LIMIT 3;
25) Provide a query that shows the most purchased Media Type.
SELECT
m.Name AS MediaType,
COUNT(t.TrackId) AS 'Most Purchased Media Type'
FROM
InvoiceLine il
INNER JOIN
Track t ON t.TrackId = il.TrackId
INNER JOIN
MediaType m ON m.MediaTypeId = t.MediatypeId
GROUP BY m.Name
ORDER BY COUNT(t.TrackId)
DESC LIMIT 1;