EzhilsreeJ / MODULE-3

EXPERIMENT-17-AGE CALCULATOR

AIM:

To create a program that calculates a person's age in years, months, and days based on their birthdate and the current date.

ALGORITHM:

1. Begin the program.
2. Define a function calculateAge() that takes six parameters: birth_day, birth_month, birth_year, current_day, current_month, and current_year.
3. Inside the function:
   • Calculate the difference in years, months, and days between the birthdate and the current date.
   • Adjust the age if the current day or month is less than the birth day or month respectively.
   • Print the calculated age in years, months, and days.
4. In the main() function:
   • Define variables birth_day, birth_month, birth_year, current_day, current_month, and current_year with predefined values representing the birthdate and the current date.
   • Call the calculateAge() function with these variables as arguments.
5. End the program.

PROGRAM:

#include <stdio.h>

void calculateAge(int birth_day, int birth_month, int birth_year,
int current_day, int current_month, int current_year) {
    int age_years, age_months, age_days;

    age_years = current_year - birth_year;
    age_months = current_month - birth_month;
    age_days = current_day - birth_day;

    if (age_days < 0) {
        age_months--;
        age_days += 31;
    }
    if (age_months < 0) {
        age_years--;
        age_months += 12;
    }

    printf("Present Age Years: %d Months: %d Days: %d\n",
             age_years, age_months, age_days);
}

int main() {
    int birth_day = 12, birth_month = 12, birth_year = 1990;
    int current_day = 8, current_month = 10, current_year = 2020;

    calculateAge(birth_day, birth_month, birth_year, current_day,
       current_month, current_year);

    return 0;
}
    

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-18-DATE VALIDITY CHECKER

AIM:

To develop a program that checks the validity of a given date.

ALGORITHM:

1. Begin the program.
2. Define a function checkDateValidity(int d, int m, int y) that takes three parameters representing the day, month, and year of the date to be checked.
3. Inside the function:
   • Declare an array daysInMonth[] to store the number of days in each month.
   • Check if the year is valid (between 1900 and 9999).
   • Check if the month is valid (between 1 and 12).
   • Adjust the number of days in February for leap years.
   • Check if the day is valid based on the number of days in the given month.
   • Print whether the day is valid or invalid.
4. In the main() function:
   • Declare variables d, m, and y to store the day, month, and year respectively.
   • Prompt the user to input the date in the format "dd/mm/yyyy".
   • Read the input date using scanf() function.
   • Call the checkDateValidity() function with the input date as arguments.
5. End the program.

PROGRAM:

#include <stdio.h>

void checkDateValidity(int d, int m, int y) {
    int daysInMonth[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    
    if (y < 1900 || y > 9999) {
        printf("Year is not valid.\n");
        return;
    }

    
    if (m < 1 || m > 12) {
        printf("Month is not valid.\n");
        return;
    }

    
    if (y % 400 == 0 || (y % 4 == 0 && y % 100 != 0)) {
        daysInMonth[1] = 29;
    }

    
    if (d < 1 || d > daysInMonth[m - 1]) {
        printf("Day is invalid.\n");
        return;
    }

    printf("Day is valid.\n");
}

int main() {
    int d, m, y;

    
    scanf("%d/%d/%d", &d, &m, &y);

    checkDateValidity(d, m, y);

    return 0;
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-19-PATTERN PRINTER

AIM:

To create a program that prints a specific pattern of numbers.

ALGORITHM:

1. Begin the program.
2. Use nested for loops to iterate over rows and columns:
   • Outer loop (r loop) iterates from 1 to 5.
   • Inner loop (c loop) iterates from 1 to 5.
   • Inside the inner loop, use conditional statements to determine the value to be printed based on the row and column indices:
     • If r and c are both 3, print "1 ".
     • If r or c is 1, 2, 4, or 5, print "3 ".
     • If r or c is 2, 3, or 4, print "2 ".
   • Print a newline character after each row.
3. End the program.

PROGRAM:

#include<stdio.h>
int main(){
    
    for(int r=1;r<=5;r++)
    {
        for(int c=1;c<=5;c++)
        {
            if(r==3&& c==3)
            printf("1 ");
            else if(c==1 || r==1 || c==5 || r==5)
            printf("3 ");
            else if(r==2 || r==3 || r==4 || c==2 || c==3 || c==4)
            printf("2 ");
            else
            printf("3 ");

        }
        printf("\n");
    }
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-20-SQUARE NUMBERS IN RANGE

AIM:

To develop a program that prints the square numbers within a given range [a, b].

ALGORITHM:

1. Begin the program.
2. Declare variables a, b, and sum of type int to store the range limits and the square of each number.
3. Prompt the user to input two integers a and b representing the range.
4. Read the input values for a and b using scanf() function.
5. Use a for loop with loop variable i initialized to a and terminating condition i <= b.
6. Inside the loop:
   • Calculate the square of i and store it in sum.
   • Check if sum is within the range [a, b]:
     • If true, print sum.
7. End the program.

PROGRAM:

#include<stdio.h>
int main()
{
    int a,b,sum=0;
    scanf("%d%d",&a,&b);
    for(int i=a;i<=b;i++)
    {
        sum=i*i;
        if(sum>=a && sum <= b)
        printf("%d ",sum);
    }
    
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-21-DIAGONAL ELEMENTS PRINTER

AIM:

To develop a program that prints the diagonal elements of a square matrix in reverse order.

ALGORITHM:

1. Begin the program.
2. Declare variables n, i, and j of type int to store the size of the square matrix and loop indices.
3. Prompt the user to input the size of the square matrix n.
4. Read the input value for n using scanf() function.
5. Declare a 2D array matrix of size n x n.
6. Use nested for loops to input the elements of the square matrix:
   • Outer loop (i loop) iterates over rows from 0 to n-1.
   • Inner loop (j loop) iterates over columns from 0 to n-1.
   • Inside the inner loop, input the matrix element at position (i, j).
7. Use a reverse for loop to print the diagonal elements of the matrix:
   • Start the loop from n-1 and iterate until 0.
   • Print the element matrix[i][i] at position (i, i) of the diagonal.
8. End the program.

PROGRAM:

#include <stdio.h>

int main() {
    int n, i, j;
    scanf("%d", &n);
    int matrix[n][n];
    for (i = 0; i < n; i++) {
        for (j = 0; j < n; j++) {
            scanf("%d", &matrix[i][j]);
        }
    }
    for (i = n - 1; i >= 0; i--) {
        printf("a[%d][%d] is %d\n", i, i, matrix[i][i]);
    }
    return 0;
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-22-ODD ELEMENTS FINDER

AIM:

To create a program that identifies and prints the odd elements of a square matrix.

ALGORITHM:

1. Begin the program.
2. Declare variables n, i, and j of type int to store the size of the square matrix and loop indices.
3. Prompt the user to input the size of the square matrix n.
4. Read the input value for n using scanf() function.
5. Declare a 2D array matrix of size n x n.
6. Use nested for loops to input the elements of the square matrix:
   • Outer loop (i loop) iterates over rows from 0 to n-1.
   • Inner loop (j loop) iterates over columns from 0 to n-1.
   • Inside the inner loop, input the matrix element at position (i, j).
7. Use nested for loops to traverse the matrix and identify odd elements:
   • Outer loop (i loop) iterates over rows from 0 to n-1.
   • Inner loop (j loop) iterates over columns from 0 to n-1.
   • Inside the inner loop, check if the element at position (i, j) is odd (i.e., matrix[i][j] % 2 != 0).
   • If the element is odd, print its position and value.
8. Print a newline after each row is traversed.
9. End the program.

PROGRAM:

#include <stdio.h>

int main() {
    int n, i, j;
    scanf("%d", &n);
    int matrix[n][n];
    for (i = 0; i < n; i++) {
        for (j = 0; j < n; j++) {
            scanf("%d", &matrix[i][j]);
        }
    }
    for (i = 0; i < n; i++) {
        for (j = 0; j < n; j++) {
            if (matrix[i][j] % 2 != 0) {
                printf("a[%d][%d] is %d\n", i, j, matrix[i][j]);
            }
        }
        printf("\n");
    }
    return 0;
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-23-ARRAY STATISTICS CALCULATOR

AIM:

To create a program that calculates and prints the sum, count of even numbers, and count of odd numbers in an array.

ALGORITHM:

1. Begin the program.
2. Prompt the user to input the size of the array size.
3. Declare an array arr of size size.
4. Use a for loop to input elements into the array:
   • Iterate i from 0 to size-1.
   • Read the input value for arr[i] using scanf() function.
5. Initialize variables sum, evenCount, and oddCount to store the sum, count of even numbers, and count of odd numbers respectively.
6. Use a for loop to traverse the array and calculate the sum and count of even and odd numbers:
   • Iterate i from 0 to size-1.
   • Update sum by adding arr[i].
   • If arr[i] is even (i.e., arr[i] % 2 == 0), increment evenCount.
   • Otherwise, increment oddCount.
7. Print the calculated sum, count of even numbers, and count of odd numbers.
8. End the program.

PROGRAM:

#include <stdio.h>

int main() {
    int size;
    scanf("%d", &size);
    
    int arr[size];
    for (int i = 0; i < size; i++) {
        scanf("%d", &arr[i]);
    }
    
    // Initialize variables to store sum, count of even and odd numbers
    int sum = 0;
    int evenCount = 0;
    int oddCount = 0;
    
    // Iterate through the array to calculate sum and count of even and odd numbers
    for (int i = 0; i < size; i++) {
        sum += arr[i];
        if (arr[i] % 2 == 0)
            evenCount++;
        else
            oddCount++;
    }
    
    // Print the results
    printf("Total Sum: %d\n", sum);
    printf("Even numbers: %d\n", evenCount);
    printf("Odd numbers: %d\n", oddCount);
    
    return 0;
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.

EXPERIMENT-24-DUPLICATE ELEMENTS FINDER

AIM:

To develop a program that identifies and counts duplicate elements in an array.

ALGORITHM:

1. Begin the program.
2. Prompt the user to input the size of the array size.
3. Declare an array arr of size size.
4. Use a for loop to input elements into the array:
   • Iterate i from 0 to size-1.
   • Read the input value for arr[i] using scanf() function.
5. Initialize a variable count to store the count of duplicate elements.
6. Use nested for loops to compare each element of the array with all subsequent elements:
   • Outer loop (i loop) iterates from 0 to size-1.
   • Inner loop (j loop) iterates from i+1 to size-1.
   • Inside the inner loop, check if arr[i] is equal to arr[j].
   • If a duplicate element is found, increment the count and break out of the inner loop.
7. Print the total number of duplicate elements found in the array.
8. End the program.

PROGRAM:

#include <stdio.h>

int main() {
    int size;
    scanf("%d", &size);

    int arr[size];
    for (int i = 0; i < size; i++) {
        scanf("%d", &arr[i]);
    }

    int count = 0;
    for (int i = 0; i < size; i++) {
        for (int j = i + 1; j < size; j++) {
            if (arr[i] == arr[j]) {
                count++;
                break;
            }
        }
    }

    printf("Total number of duplicate elements found in array = %d\n", count);

    return 0;
}

SAMPLE OUTPUT :

OUTPUT :

RESULT:

Thus the required program is written and executed successfully.