Synacor Challenge

Source code of my solution to the Synacor Challenge.

I've put myself a personal challenge: do not use any third-party packages (only use built-in Python features).

Prerequisites

Python >= 3.8.

Installation

Clone this repo.

Usage

$ python run.py materials/challenge.bin

Press CTRL+C to stop.

Codes

Important

Spoilers below.

You have to find 8 codes scattered along the challenge, and submit each of them on the challenge website to validate your progress.

Begin by implementing a virtual machine able to execute the challenge's binary file: follow the architecture specs.

First code

Found in the architecture specs.

Second code

Found once you implemented all the basic opcodes mentioned in the specs (0, 19, and 21).

Third code

Found once all the opcodes have been implemented and self-tests have passed.

Fourth code

Found in the text adventure game by using the tablet at the very beginning.

Fifth code

Found in the text adventure game on a wall in a twisty passage by walking in the caverns.

At this point of the challenge, I made it so I am able to automate all the actions instead of manually typing: python run.py materials/challenge.bin --actions=solutions/text_adventure_game.txt

Sixth code

Found in the text adventure game by using the teleporter device.

The teleporter device can be found after solving the equation of the strange monument in the central hall after collecting all the five coins (red, blue, shiny, concave and corroded): _ + _ * _^2 + _^3 - _ = 399.

Seventh code

Note

WIP: I am here.

The teleporter device must be used a second time, but not before setting register #8 to some very specific number.

At this point of the challenge, I had to implement a debugger. It's hooked to the virtual machine's input system. The following commands are available:

!dump example.dump dumps the current state of the virtual machine to a file using a custom binary format. This file can be loaded back (the format is automatically recognized by the virtual machine): python run.py example.dump
!reg displays the registers state
- !reg <a> <b> sets register's <a> value to <b>
!sta displays the stack state
!mem displays the memory state at the current address pointer
- !mem <a> displays the memory state at the given address <a>

Eighth code

I don't know yet.

EpocDotFr / synacor-challenge