tried using jql

[Zane (She/They)]

Hello,

I used brew install and have a sample.json file inside my folder directory. I was trying the commands as shown on the README, but could not get any data returned or get "unable to parse input".

my JSON

{
  "employee": {
    "name":"employee01",
    "age": "30",
    "city":"New York"
  },
  "boss" : {
    "name": "boss person",
    "role": "regional supervisor"
  },
  "stuff" : {
    "a": 1,
    "b": 2,
    "c": 3
  }

}

the commands i tried:

• jql "boss" sample.json among variations
• jql "stuff{'a'}" sample.json
• jql employee -s -r sample.json
• jsql "employee['city']" -s -r sample.json
  all of these return "unable to parse"

what am i doing wrong here?

[Davy Duperron]

Hi @PythonCoderUnicorn,

You're almost there, it's just a matter of single / double quotes usage. Basically jql is very strict about JSON keys and always needs key selectors to be double-quoted (https://github.com/yamafaktory/jql?tab=readme-ov-file#%EF%B8%8F-usage).

In your examples, it should like:

jql '"boss"' sample.json 
{
  "name": "boss person",
  "role": "regional supervisor"
}

jql '"stuff""a"' sample.json 
1

Please notice that in the last example, there's no need to have a . between keys.

Then using the -s flag is not really useful here since it's basically continuously reading the any command you would pipe in like docker logs with the --follow flag (https://github.com/yamafaktory/jql?tab=readme-ov-file#read-a-stream-of-json-data-line-by-line).

Finally the -r flag is only useful if you pick a string primitive via your selectors and want to strip the double quotes (https://github.com/yamafaktory/jql?tab=readme-ov-file#write-to-stdout-without-json-double-quotes).

I hope that it will help :) .

[Zane (She/They)]

@yamafaktory
Thank you for your reply. I ran your examples and it worked. 🎉
Thanks for the tool.

[Davy Duperron]

Glad it helped!

Closing the issue then.