Generic type in declaration parsed as binary expression
Sjord opened this issue · comments
IEnumerable<Clz> a = new Clz[1];
Expected:
(compilation_unit [0, 0] - [0, 32]
(global_statement [0, 0] - [0, 32]
(local_declaration_statement [0, 0] - [0, 32]
(variable_declaration [0, 0] - [0, 31]
type: (generic_name [0, 0] - [0, 16]
(identifier [0, 0] - [0, 11])
(type_argument_list [0, 11] - [0, 16]
(predefined_type [0, 12] - [0, 15])))
(variable_declarator [0, 17] - [0, 31]
(identifier [0, 17] - [0, 18])
(equals_value_clause [0, 19] - [0, 31]
(array_creation_expression [0, 21] - [0, 31]
(array_type [0, 25] - [0, 31]
type: (predefined_type [0, 25] - [0, 28])
rank: (array_rank_specifier [0, 28] - [0, 31]
(integer_literal [0, 29] - [0, 30]))))))))))
Actual:
(compilation_unit [0, 0] - [0, 32]
(global_statement [0, 0] - [0, 32]
(expression_statement [0, 0] - [0, 32]
(assignment_expression [0, 0] - [0, 31]
left: (binary_expression [0, 0] - [0, 18]
left: (binary_expression [0, 0] - [0, 15]
left: (identifier [0, 0] - [0, 11])
right: (identifier [0, 12] - [0, 15]))
right: (identifier [0, 17] - [0, 18]))
(assignment_operator [0, 19] - [0, 20])
right: (array_creation_expression [0, 21] - [0, 31]
(array_type [0, 25] - [0, 31]
type: (identifier [0, 25] - [0, 28])
rank: (array_rank_specifier [0, 28] - [0, 31]
(integer_literal [0, 29] - [0, 30]))))))))