SMPL model version

[VickyLi2002]

Hi @skhu101 ,Thanks a lot for sharing this very excellent work !
I have a problem about the smpl model during evaluation.I downloaded and used the SMPL_NEUTRAL of version 1.1.0 for Python2.7 from https://smpl.is.tue.mpg.de/download.php.But this smpl model has 300 shape PCs which means the shape of parameter'shapedirs' is (6890,3,300) instead of (6890,3,10).

This would be incredibly helpful !
Thanks a lot !

[Shoukang Hu]

Hi, thanks for your interest in our work. The first 10 shape PCs should be used. If you have further questions, please let me know.

[VickyLi2002]

Thanks for your help!!!
I have solved this problem.

[Arnab Dey]

How did you solve the problem?

[VickyLi2002]

How did you solve the problem?

import pickle
def smpl_pro():
    model_paths = {
                # 'neutral': os.path.join(model_dir, NEUTRAL_PATH)
                # 'neutral': os.path.join(model_dir)
                'neutral': os.path.join('assets/SMPL_NEUTRAL.pkl')
            }
    #import smpl        
    with open(model_paths['neutral'], 'rb') as f:
                smpl_model = pickle.load(f, encoding='latin1')
    #reshape shapedirs
    smpl_model['shapedirs'] = smpl_model["shapedirs"][:,:,:10]
    #rewrite smpl
    with open('smpl/assets/updated_data.pkl', 'wb') as f:
        pickle.dump(smpl_model, f)

    # with open(model_paths['neutral'], 'rb') as f:
    #         smpl_model = pickle.load(f, encoding='latin1')
    #check again
    with open('smpl/assets/updated_data.pkl', 'rb') as f:
            smpl_model = pickle.load(f, encoding='latin1')
    for key in smpl_model.keys():
        try:
            print(key,":",smpl_model[key].shape)
        except:
            print(key,":",smpl_model[key])