Question: How to allocate an array of structs?

[kojix2]

Hi!

How to allocate an array of structs?
I tried the following code, but it does not work as expected. It may be because the same area is released twice.

require 'fiddle/import'

A = Fiddle::Importer.struct [
  'int x',
  'int y'
]

as = Fiddle::Pointer.malloc(A.size * 3)

structs = Array.new(3){ |i|
  size = A.size
  A.new(as.to_i + i * size, size)
}

Thank you.

[Sutou Kouhei]

A.new's second argument is free function not size: A.new(as.to_i + i * size)

BTW, you must free as.

[kojix2]

It's true. I was wrong.

require 'fiddle/import'

A = Fiddle::Importer.struct [
  'int x',
  'int y'
]

as = Fiddle::Pointer.malloc(A.size * 3)

structs = Array.new(3){ |i|
  size = A.size
  A.new(as.to_i + i * size)
}

When a Fiddle::Pointer is collected in garbage collection, is the memory of the pointer not automatically released?
That is, if no function is specified to release it, it will remain until (or even after?) Ruby exits?

[Sutou Kouhei]

You can use the second argument for Fiddle::Pointer.malloc for free function: Fiddle::Pointer.malloc(A.size * 3, Fiddle::RUBY_FREE).

You can also use block:

Fiddle::Pointer.malloc(A.size * 3, Fiddle::RUBY_FREE) do |as|
  # ...
end

[kojix2]

Wow. This is very useful.
Good to hear.