Cron is not scheduling as per the provided string
dhamechavivek95 opened this issue · comments
@selwin
I have my schedule.py file
from redis import Redis
from rq_scheduler import Scheduler
from my_file import My_Function
def run():
r = Redis()
scheduler = Scheduler(connection=r)
scheduler.cron("0 * * * *", func=My_Function,
queue_name=My_Queue_Name)
Now in my_file.py
from dateTime import dateTime, timedelta
def My_Function():
try:
Logger.log.warning("$" * 40)
from_time = \
int(datetime.timestamp(datetime.now() - timedelta(hours=2)))
to_time = int(datetime.timestamp(datetime.now() - timedelta(hours=1)))
Logger.log.warning("Email")
Logger.log.warning("From Time")
Logger.log.warning(from_time)
Logger.log.warning("To Time")
Logger.log.warning(to_time)
It runs exactly 22 times in an hour at 10:31 and 10:32 and within a difference of seconds. I have my script in production, Please help me with this.
@dhamechavivek95 TTBOMK this is caused due to duplication of jobs. The problem is that previously scheduled jobs were run when you restarted your scheduler / worker.
I had faced the same problem, check out the solution given by @ipmb here - #51 (comment)
It basically subclasses rqscheduler and first clears the previous jobs and then registers new one's