child process closing immediately

[Phil]

If you're not familiar with icecast, it's a multimedia server.

When I run icecast -c ./icecast/icecast.xml in the terminal, it starts an icecast server, which stays alive.

So I want to run that command alongside my node.js process, every time I run gulp.

I added the following to my gulpfile.

import exec from 'gulp-exec'

...

const icecastDir = path.resolve(`${__dirname}/icecast/`)

...

gulp.task(`icecast`, () => {
  return exec(`/usr/local/bin/icecast -c ${icecastDir}/icecast.xml`)
    .on(`data`, () => {
      console.log(`data`)
    }) 
    .on(`error`, () => {
      console.log(`error`)
    }) 
    .on(`end`, () => {
      console.log(`end`)
    }) 
    .on(`close`, () => {
      console.log(`error`)
    }) 
    .on(`readable`, () => {
      console.log(`readable`)
    }) 
})

When I run the command gulp icecast in my terminal, gulp says Starting 'icecast'... and then immediately terminates. None of the callbacks fire. I'd really like it to stay alive until I cmd-c the gulp process.

[Rob Richardson]

You're not piping any filenames into it. In this case, don't use gulp-exec and use child_process#exec directly.

[Phil]

Thx for this response, by the way. Closing.