[Bug report] 关键词提取模式，`segment(code,jiebar)` 方式报错。
BruceZhaoR opened this issue · comments
Reproducible example:
library(jiebaR)
#关键词提取
kseg = worker(type = "keywords")
> segment("我爱北京***",kseg)
Error: "segment" %in% class(jiebar) is not TRUE
> kseg["我爱北京***"]
8.9954 4.6674
"***" "北京"
> kseg <= "我爱北京***"
8.9954 4.6674
"***" "北京" Test Mix Segment mode
> mseg = worker()
> segment("我爱北京***",mseg)
[1] "我" "爱" "北京" "***"
> mseg["我爱北京***"]
[1] "我" "爱" "北京" "***"
> mseg <= "我爱北京***"
[1] "我" "爱" "北京" "***"My Env
> devtools::session_info()
Session info ------------------------------------------------------------
setting value
version R version 3.2.4 (2016-03-10)
system x86_64, mingw32
ui RStudio (0.99.879)
language (EN)
collate Chinese (Simplified)_China.936
tz Asia/Shanghai
date 2016-03-21
Packages -----------------------------------------------------------------
package * version date source
...
jiebaR * 0.8 2016-01-30 CRAN (R 3.2.3)
jiebaRD * 0.1 2015-01-04 CRAN (R 3.2.3)
memoise 1.0.0 2016-01-29 CRAN (R 3.2.3)
microbenchmark * 1.4-2.1 2015-11-25 CRAN (R 3.2.3)
Rcpp 0.12.3 2016-01-10 CRAN (R 3.2.3)
...
segment 是对分词的，keywords(code, jiebar) 是对关键词的
了解了，怪我没有仔细看说明文档。感觉这个 <= 是通用的。:blush: