`f<Shift>x` no longer opens the link at `x` in a new tab
wchargin opened this issue · comments
I just upgraded to Vimium 1.60. An important piece of functionality appears to have regressed.
Previously, if I were to press f and a link target ABC were to appear, then I could press ab<Shift-c> to open the link in a new tab. That is, fab<Shift-c> behaved in the same way as <Shift-f>abc.
This is no longer the case. Now, pressing <Shift-x> for any x while in f-mode deactivates f-mode. That is, pressing f<Shift-a> or fab<Shift-c> is the same as pressing no key at all.
I noticed this behavior on Chrome 60.0.3112.90. I then upgraded to Chrome 61.0.3163.79, which has the same behavior.
(Edited to clarify key notation.)
OS version:
$ uname -a
Linux wchargin-t440s 4.10.0-32-generic #36~16.04.1-Ubuntu SMP Wed Aug 9 09:19:02 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux
$ lsb_release -a
No LSB modules are available.
Distributor ID: LinuxMint
Description: Linux Mint 18.2 Sonya
Release: 18.2
Codename: sonya
I'll look into this.
Thank you!
One more note: the same happens with <ShiftDown>fabc<ShiftUp>, which used to open abc in a new tab. Now, I am required to release shift before pressing the link target: only <ShiftDown>f<ShiftUp>abc works.
This should be fixed in v1.60.1 (which is rolling out to Chrome users now).
You're the best—thanks so much!