获取token,参数值错误,直接抛异常,而且异常信息不是json,如何解析code值,代码如下
xyZangGit opened this issue · comments
Tim-Zhang commented
Map<String, Object> appAccessTokenBody = new HashMap<>();
appAccessTokenBody.put("app_id", Constant.FeiSuOpenAiAppId);
appAccessTokenBody.put("app_secret", Constant.FeiSuOpenAiAppSecret);
try {
RawResponse resp = getClient().post(Constant.FeiShuAppAccessToken, appAccessTokenBody, AccessTokenType.Tenant);
// 处理结果
System.out.println(resp.getStatusCode());
System.out.println(Jsons.DEFAULT.toJson(resp.getHeaders()));
System.out.println(new String(resp.getBody()));
System.out.println(resp.getRequestID());
} catch (Exception e) {
e.printStackTrace();
}