Show() to generate joins

[Constandinos Iezekiel]

How can i get from show() the same details as index()
For example.
Tweet.query()
.where(this.params.query)
.join('user')
.end((err, models) => {
this.respond(err || models, ['id', 'body', 'created_at', 'user']);
});

But for show() where i can add join('user') to also select user into model
Tweet.find(this.params.route.id, (err, model) => {
this.respond(err || model);
});

[Keith Horwood]

You can either do use the index query with Tweet.query({id: this.params.id}).join('user').end(...) or you can do (in the find call):

[...].find((err, model) => {
  if (err) {
    return this.respond(err);
  }

  model.include((err, user) => {
    // include runs a separate query to grab the user model, returns it as a parameter
    // does matching based on parameter name
    this.respond(err || model, ['id', 'body', 'created_at', 'user']);
  });

});