datetime2 transformed to the datetime when datetime2 in TVP.
NextStalker opened this issue · comments
Describe the bug
Two records are not equal.
2018-10-30 10:32:53.2415414
2018-10-30 10:32:53.2400000
Steps to reproduce
create table [dbo].[TestTable]( [Id] [int] identity(1,1) not null, [MyDatetime2] [datetime2](7) not null ) on [primary]
create type [dbo].[datetime2List] as table( [myDatetime2] [datetime2](7) not null, [name] [nvarchar](50) not null)
create procedure [dbo].[InsertDateTime2] @myDatetime2 datetime2 as insert into TestTable(MyDatetime2) values(@myDatetime2)
create procedure [dbo].[InsertDateTime2List] @datetime2List as datetime2List readonly as insert into TestTable(MyDatetime2) select myDatetime2 from @datetime2List
public class DateTime2Model { public DateTime MyDatetime2 { get; set; } }
[Sql(Schema = "dbo")] public interface IDateTime2Repository { void InsertDateTime2(DateTime2Model dateTime2Test); void InsertDateTime2List(IList<DateTime2Model> dateTime2TestList); }
var model = new DateTime2Model { MyDatetime2 = DateTime.UtcNow };
var repo = connection.As<IDateTime2Repository>();
repo.InsertDateTime2(model);
var list = new List<DateTime2Model> { model };
repo.InsertDateTime2List(list);
Expected behavior
Two records are equal.
- Dotnet version: [dotnet462]
- Database: [SQL Server]
- Library version: [6.2.6]
This is fixed in master. Will be in the 6.2.7 release
Hi, @jonwagner do you have approximate date for release 6.2.7 ?
Just released.