Can't get character groups (`[]`) to work

[Steven Lu]

Here's an example:

echo $'1,fE+2,a\n2,2E+2,b' | q -d, 'select * from - where c2 like "%[2]E+2"'

That doesn't work, I can't get any [] to work, even when escaped with a backslash. It's not clear if this is simply a missing feature or what.

[David Ongaro]

I suppose you're confusing pattern matching via like with regexp matching? The SQLite like operator only supports the % and _ wildcards and has nothing to do with regexp (e.g. see https://www.sqlitetutorial.net/sqlite-like/). However if the regexp extension is active, you can use the regexp operator. E.g. this is working for me:

$ echo $'1,fE+2,a\n2,2E+2,b' | q -d, 'select * from - where c2 regexp "[2]E\+2"'
2,2E+2,b

[Harel Ben-Attia]

thanks @bitti for the answer. Indeed the regexp syntax can be used for such a use-case.

[Steven Lu]

Thank you for the clarification!