Option no-sort doesn't seem to work on gulp 5.0.0
tallenglish opened this issue · comments
What were you expecting to happen?
Only changing between gulp v4.0.2 and v5.0.0 (all other plugins stay the same and latest versions).
Issue is only really a problem for JavaScript files where the order of the files being concat is vital for plugins that depend on others - like jQuery needing to be first.
I am using ESM gulpfile, as required by latest gulp-autoprefixer v9.0.0 now.
Using the following to keep the order of input sources unsorted (mainly required for JavaScript dependencies).
What actually happened?
Works as expected for gulp v4.0.2 with "no-sort" option, however array is still sorted when using v5.0.0 with same option.
Please give us a sample of your gulpfile
return gulp.src(src, { "no-sort": true })
.pipe(gulp_concat(file))
.pipe....
In this case the src is an array of files similar to the following, and need to be concat in the same order:
const src = [
"a.js",
"b.js",
"c.js",
"d.js"
];
Only change needed to break is upgrading from gulp v4.0.2 to v5.0.0
Terminal output / screenshots
None
Please provide the following information:
- OS & version: Debian Linux bookworm (all latest updates)
- node version (run
node -v): 20.11.0 - npm version (run
npm -v): 10.5.1 - gulp version (run
gulp -v): 5.0.0
Additional information
None
I have tried using gulp-order plugin to fix the order in a pipe after gulp.src, however it doesn't seem to work either on v5.0.0, or has no effect at least.
One final note I forgot to mention, the documentation says the option is "nosort" (no dash), I tried that and it didn't work on either v4.0.2 or v5.0.0. I found the dash option from other documentation.
I'm seeing the same. When given an array of ["path/filename.js", ...], the output from gulp.src appears sorted in alphabetical order using the base filename without the leading path.
I never needed the "nosort" option with gulp 4.02. I also tried src options no-sort, nosort, and noSort without success.
To resolve this issue, try this option. Create an array with paths in the order you need, as you wrote above.
const scriptsList = [
'node_modules/vanilla-lazyload/dist/lazyload.js',
'node_modules/lightgallery/lightgallery.min.js',
'app/js/main.js'
]
In order for the gulp-order plugin to work correctly and create a strict order like in an array, you need to specify the names of specific files
return src(scriptsList, { allowEmpty: true })
.pipe(order([
'lightgallery.min.js',
'lazyload.js',
'main.js',
]))
