Isn't `slog.Fatal()` meant to call `os.Exit(1)`?

[George L. Yermulnik]

I'm expecting slog.Fatal to call os.Exit(1) to reflect log.Fatal(), but this is not happening.
Is this expected or am I doing something incorrect?

package main

import (
        "github.com/gookit/slog"
)

func main() {
        slog.Info("info log message")
        slog.Fatal("fatal log message")
        slog.Info("info log message")
}

> go run ./main.go ; echo $?
[2024/04/05T19:13:52.904] [application] [INFO] [main.go:8,main] info log message
[2024/04/05T19:13:52.904] [application] [FATAL] [main.go:9,main] fatal log message
[2024/04/05T19:13:52.904] [application] [INFO] [main.go:10,main] info log message
0

[George L. Yermulnik]

https://github.com/gookit/slog/blob/master/common.go#L56-L58

	// FatalLevel level. Logs and then calls `logger.Exit(1)`. It will exit even if the
	// logging level <= FatalLevel.
	FatalLevel Level = 200

[George L. Yermulnik]

I'd expect Panic to panic(), Fatal to os.Exit(1), and everything else to just print.
Am I misinterpreting the idea and the code?

[Inhere]

hi @yermulnik logger.ExitFunc is not set by default, so Fatal will not exit.

You can set it:

// for std logger
slog.SetExitFunc(os.Exit)

// for new logger
l := slog.New(func(l *slog.Logger) {
	l.ExitFunc = os.Exit
})

[George L. Yermulnik]

@inhere Thanks for the pointer 👍🏻