THE PROBLEM 4.4.1-6 is WRONG

[OneirdyniaYi]

From the definition of the follow set, we know,1.follow(bterm) = first(bexpr') except ∈
and 2.bexpr' => ∈ follow(bterm) = follow(bexpr)
In a word, follow(bterm) = {$,),or}

[sicer]

That's right. We can see a previous issue for correct answer: #60