Invariants ignored by `prove`
leonardoalt opened this issue · comments
constructor of LValue
interface constructor()
creates
uint x := 0
uint y := 2
invariants
x == 0
y == 2
behaviour f of LValue
interface f()
storage
x => 0
y => 2
Also not sure what the expected behavior here is, but I get:
$ ./result/bin/act prove --file lvalue.act
============
Invariant "(LValue.x == 0)" of "LValue": Q.E.D
Shouldn't y == 2 also be proved? Or am I missing something?
hmmmm I just ran this with current master and it seems to be proving both of them on my machine. Can you still reproduce this @leonardoalt?
============
Invariant "(LValue.x == 0)" of "LValue": Q.E.D ✨
============
Invariant "(LValue.y == 2)" of "LValue": Q.E.D ✨