Need IterableExtension<E> with anyIndexed and everyIndexed
darkstarx opened this issue · comments
Serj Elokhin commented
Could you implement anyIndexed
and everyIndexed
please?
extension IterableExt<E> on Iterable<E>
{
bool everyIndexed(final bool Function(int i, E e) test)
{
var index = 0;
for (final element in this) {
if (!test(index, element)) return false;
}
return true;
}
bool anyIndexed(final bool Function(int index, E element) test)
{
var index = 0;
for (final element in this) {
if (test(index, element)) return true;
}
return false;
}
}
Lasse R.H. Nielsen commented
There is now an indexed
extension getter on Iterable
in the platform libraries. You can do someIterable.indexed.any((iv) => indexTest(iv.$1) && valueTest(iv.$2))
.
I hope to get better syntax for destructing f directly in the parameter list in the future.