Parsing KEGG get() entries prints the entire dict
smdabdoub opened this issue · comments
I found two instances of print statements in the _parse function that print the entire parsed record whenever parsing is done. Lines 1399 and 1438
from bioservices import KEGG, KEGGParser
s = KEGG()
kp = KEGGParser()
rec = s.get("hsa:7535", parse=True)
rec = kp.parse(s.get("hsa:7535"))
On both of those last two lines, the entire parsed dictionary is printed, key and value.
@smdabdoub indeed, this was a regression in version 1.8.3, which is now fixed in 1.8.4