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cassicakes / booktown

Queries upon queries in Booktown, USA

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##Order

  1. Find all subjects sorted by subject select subject from subjects order by subject;

  2. Find all subjects sorted by location select subject from subjects order by location;

##Where

  1. Find the book "Little Women" select * from books where title in ('Little Women’);

  2. Find all books containing the word "Python" select * from books where title ilike '%Python%’;

  3. Find all subjects with the location "Main St" sort them by subject select subject from subjects where location='Main St' order by subject;

##Joins

  • Find all books about Computers list ONLY book title select title from subjects s join books b on b.subject_id= s.id where subject ='Computers’;

  • Find all books and display ONLY

    • Book title

    • Author's first name

    • Author's last name

    • Book subject

      select b.title, a.first_name, a.last_name, s.subject from books b join subjects s on b.subject_id = s.id join authors a on a.id = b.author_id;

  • Find all books that are listed in the stock table

    • Sort them by retail price (most expensive first)

    • Display ONLY: title and price

      select books.title, stock.retail from stock join editions on editions.isbn = stock.isbn join books on editions.book_id = books.id order by stock.retail desc;

  • Find the book "Dune" and display ONLY

    • Book title

    • ISBN number

    • Publisher name

    • Retail price

      select b.title, e.isbn, p.name, s.retail from books b join editions e on b.id = e.book_id join stock s on s.isbn = e.isbn join publishers p on p.id = e.publisher_id where b.title = 'Dune';

  • Find all shipments sorted by ship date display ONLY:

    • Customer first name

    • Customer last name

    • ship date

    • book title

      select c.first_name, c.last_name, s.ship_date, b.title from books b join editions e on b.id = e.book_id join shipments s on s.isbn = e.isbn join customers c on c.id = s.customer_id order by s.ship_date;

##Grouping and Counting

  1. Get the COUNT of all books select count(*) from books;

  • Get the COUNT of all Locations select count(location) from subjects;

  • Get the COUNT of each unique location in the subjects table. Display the count and the location name. (hint: requires GROUP BY). select location, count(location) from subjects group by location;

  • List all books. Display the book_id, title, and a count of how many editions each book has. (hint: requires GROUP BY and JOIN) select b.id, b.title, count(e.edition) from books b join editions e on e.book_id = b.id group by b.id;

####YAY! You're done!!

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Queries upon queries in Booktown, USA