Implement unary is-defined operator ?, prohibit undefined .IF argument, remove .IFDEF

Question

Implement unary is-defined operator ?, prohibit undefined .IF argument, remove .IFDEF

boeckmann opened this issue a year ago · comments

At the moment ? is used to return an undefined value. But the following usage seems to be more convinient:

.IF ?VICE
.ENDIF

Testing for undefined value should be much more common than expressing an undefined value. Undefined value will become .?.

Undefined arguments to .IF can be prohibited. .IFDEF is redundant and can be removed. Both not decided yet.

Bernd Böckmann · Answer 1 · Wed Apr 26 2023 16:00:34 GMT+0800 (China Standard Time)

? and .? are implemented by dd2eda9. Regarding .IF and .IFDEF, a final decision is not made yet.

Fred N. van Kempen · Answer 2 · Wed Apr 26 2023 23:31:00 GMT+0800 (China Standard Time)

Problem is, most developers are used to working with if/ifn/ifdef/ifndef, and only a few use the more esoteric ? operators, even more so if those developers are also using C or C++ .. I am not going to do this, unless I get specific requests for it. On Wednesday, April 26, 2023 at 03:56:39 AM EDT, Bernd Böckmann ***@***.***> wrote: At the moment ? is used to return an undefined value. But the following usage seems to be more convinient: .IF ?VICE .ENDIF .IFDEF is then redundant and could get removed. The undefined value becomes .?. — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>

Bernd Böckmann · Answer 3 · Sun Apr 30 2023 02:59:43 GMT+0800 (China Standard Time)

leave .ifdef, .ifndef in for now.