`from_xml` not found

[Jaume Zaragoza]

Trying to compile the example in the documentation but it doesn't compile despite from_xml feature being enabled.

use std::fs;
use srx::SRX;

fn main() {
    let srx = SRX::from_xml(&fs::read_to_string("data/language_tools.segment.srx").unwrap())?;
    let english_rules = srx.language_rules("en");

    println!("Hello, world!");
    assert_eq!(
        english_rules.split("e.g. U.K. and Mr. do not split. SRX is a rule-based format.").collect::<Vec<_>>(),
        vec!["e.g. U.K. and Mr. do not split. ", "SRX is a rule-based format."]
    );
}

error[E0599]: no function or associated item named `from_xml` found for struct `SRX` in the current scope
 --> src/main.rs:5:20
  |
5 |     let srx = SRX::from_xml(&fs::read_to_string("data/language_tools.segment.srx").unwrap())?;
  |                    ^^^^^^^^ function or associated item not found in `SRX`

error[E0277]: the `?` operator can only be used in a function that returns `Result` or `Option` (or another type that implements `Try`)
  --> src/main.rs:5:15
   |
4  | / fn main() {
5  | |     let srx = SRX::from_xml(&fs::read_to_string("data/language_tools.segment.srx").unwrap())?;
   | |               ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ cannot use the `?` operator in a function that returns `()`
6  | |     let english_rules = srx.language_rules("en");
7  | |
...  |
12 | |     );
13 | | }
   | |_- this function should return `Result` or `Option` to accept `?`
   |
   = help: the trait `Try` is not implemented for `()`
   = note: required by `from_error`

error: aborting due to 2 previous errors

[package]
name = "rsegment"
version = "0.1.0"
edition = "2018"

[dependencies]
srx = { version = "0.1.3", features = ["from_xml"] }

[Jaume Zaragoza]

Sorry, I meant from_str

[Jaume Zaragoza]

use std::{fs, str::FromStr}; was missing, my fault.