What's the confusing $6 here, there seams to be only 5 parts to the rule

[James Peach]

compiler_series/ep1/conj.y

Line 157 in c9b757d

 functions:                      functions identifier1 { ctx.defun($2); ++ctx; } paramdecls colon1 stmt1 { ctx.add_function(M($2), M($6)); --ctx; } 

what am I missing here?

[James Peach]

functions identifier1 { ctx.defun($2); ++ctx; } paramdecls colon1 stmt1

does { ctx.defun($2); ++ctx; } count as a part?

[Joel Yliluoma]

Yes, the semantic action counts as a part.