Path expression to select all Java constructors

[David Dooling]

From @ElderMael in atomist-community:

I have several classes that expose two constructors (default and one with all the fields they have). I am unable to create a expression that selects both constructors. It is selecting only the default constructor. So far I only have this: //JavaConstructor()

public edit(project: Project) {

        const eng: PathExpressionEngine = project.context.pathExpressionEngine;

        let superTypesToExclude = this.excludingSuperTypes ? this.excludingSuperTypes.split("-") : [];

        eng.with<JavaSource>(project,
            `//JavaSource()`,
            javaSourceCode => {

                eng.with<JavaType>(javaSourceCode,
                    `//JavaType()[.pkg()='${ this.packageOfTypesToAnnotate }']`,
                    javaType => {

                        let isTheSuperType = superTypesToExclude.some((superType) => {

                            let isSameType = superType === javaType.name;

                            return isSameType;

                        });

                        if (isTheSuperType) {
                            return;
                        }

         
                        eng.with<JavaConstructor>(javaType, '//JavaConstructor()', javaConstructor => {
                            javaConstructor.addAnnotation(this.annotationPackage, this.annotationName);
                        });

                    });

            });

    }

Reference: https://atomist-community.slack.com/files/U2RL76AMS/F78FVA5K7/Edit_Method.js

[David Dooling]

@ElderMael we will need to discuss in the community how to best move this forward in the new world.