C++ lambda return type parsed as variable name

[Kent]

Description

Lambda return type in C++ is parsed as a variable name if the lambda is placed inside a scope.

Example:

void foo() {
    auto sum = [](int a, int b) -> int {
        return a + b;
    };
}

[Mazen Elkashef]

Hey @ToxicPie, thanks for the report!

Could you please fill-in the template (you can copy the template by creating a new issue), the part I am most interested in is the Expected Behavior section.

I tried to check the scope for int a and it seems to match the int in lambada, knowing more about what you think the behavior should be, would be helpful.

[no-response]

This issue has been automatically closed because there has been no response to our request for more information from the original author. With only the information that is currently in the issue, we don't have enough information to take action. Please reach out if you have or find the answers we need so that we can investigate further.