Array.IndexOf always returns 0 when it found the first element
dynamicboy opened this issue · comments
Version:2.8.7
Details:
Small Visual Basic
ArrayGroup1[1] = 1
ArrayGroup1[2] = 2
ArrayGroup1[3] = 3
For I = 0 To 3
Index = Array.IndexOf(ArrayGroup1, I, 1, True)
TW.WriteLine("Index = " + Index)
Next
Output:
Index = 0
Index = 0
Index = 1
Index = 2
I found that I didn't add a test for the IndexOf method, so I did, and fixed this issue. I also hide the Text.GetIndexOf method and added a Text.IndexOf method to be consistent with the Array.IndexOf.
I updated sVB to version 2.8.7.3 and you can now download it:
https://marketplace.visualstudio.com/items?itemName=ModernVBNET.sVBInstaller
and try your code, which by the way can be shorten to this:
```
ArrayGroup1 = {1, 2, 3}
For I = 0 To 3
Index = ArrayGroup1.IndexOf(I, 1, True)
TW.WriteLine("Index = " + Index)
Next
```
Thanks.
…________________________________
From: dynamicboy ***@***.***>
Sent: Friday, December 8, 2023 11:46 PM
To: VBAndCs/sVB-Small-Visual-Basic ***@***.***>
Cc: Subscribed ***@***.***>
Subject: [VBAndCs/sVB-Small-Visual-Basic] Array.IndexOf always returns 0 when it found the first element (Issue #37)
Version:2.8.7
Details:
Small Visual Basic
ArrayGroup1[1] = 1
ArrayGroup1[2] = 2
ArrayGroup1[3] = 3
For I = 0 To 3
Index = Array.IndexOf(ArrayGroup1, I, 1, True)
TW.WriteLine("Index = " + Index)
Next
Output:
Index = 0
Index = 0
Index = 1
Index = 2
—
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