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Sunny-117 / js-challenges

✨✨✨ Challenge your JavaScript programming limits step by step

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concat

FailurMan opened this issue · comments

commented 
//ts实现数组的concat功能
type Concat<T extends any[], U extends any[]> = [...T, ...U];
type Result = Concat<[1], [2]>;
commented

个人觉得将any换成unknown会更严谨一些