对象字符串转化成树形结构
Sunny-117 opened this issue · comments
Sunny commented
let strarr = {
'a-b-c-d':1,
'a-b-c-e':2,
'a-b-f':3,
'a-j':4
}
let obj = {
a:{
b:{
c:{
d:1,
e:2
},
f:3
},
j:4
}
}
fencer commented
let strarr = {
'a-b-c-d':1,
'a-b-c-e':2,
'a-b-f':3,
'a-j':4
}
const data = Object.keys(strarr).reduce(function (acc, cur) {
const _keys = cur.split('-');
let tmp = acc;
_keys.forEach((key, idx) => {
if (idx === _keys.length - 1) {
tmp[key] = strarr[cur];
} else {
if (!tmp[key]) tmp[key] = {};
tmp = tmp[key];
}
});
return acc;
}, {});
xiaoy commented
function strToTree(strArr){
let objTree = {}
const dfs = (arr,obj,val) => {
for(let i=0; i<arr.length-1; i++){
if(!obj[arr[i]]) obj[arr[i]] = {}
obj = obj[arr[i]]
}
obj[arr[arr.length-1]] = val
}
for(let str in strArr){
dfs(str.split('-'),objTree,strArr[str])
}
return objTree
}
console.log(strToTree(strArr))
kangkang123269 commented
- 迭代
function strObjtoTree(strarr) {
let obj = {};
for (let key in strarr) {
let propertyNames = key.split('-');
let lastPropertyName = propertyNames.pop();
let nestedObj = obj;
for (let propertyName of propertyNames) {
nestedObj[propertyName] = nestedObj[propertyName] || {};
nestedObj = nestedObj[propertyName];
}
nestedObj[lastPropertyName] = strarr[key];
}
return obj
}
- 递归
function convertToObject(strarr) {
const result = {};
for (let key in strarr) {
const keys = key.split('-');
let obj = result;
for (let i = 0; i < keys.length - 1; i++) {
const k = keys[i];
obj[k] = obj[k] || {};
obj = obj[k];
}
obj[keys[keys.length - 1]] = strarr[key];
}
return result;
}