contacts[i][firstName] 与 contacts[i].firstName 的区别在哪呢？
Ccneedmoney opened this issue · comments
Challenge Profile Lookup has an issue.
User Agent is: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.100 Safari/537.36.
Please describe how to reproduce this issue, and include links to screenshots if possible.
My code:
//初始化变量
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["Javascript", "Gaming", "Foxes"]
}
];
function lookUp(firstName, prop){
// 请把你的代码写在这条注释以下
for(var i=0;i<contacts.length;i++){
//if(firstName == contacts[i][firstName]){ //使用此句时结果不通过
if(firstName == contacts[i].firstName){ //使用此句时结果通过
if(contacts[i].hasOwnProperty(prop)){ return contacts[i][prop];}
else { return "No such property"; }
}
}
return "No such contact";
// 请把你的代码写在这条注释以上
}
// 你可以修改这一行来测试你的代码
lookUp("Akira", "likes");