`::#` doesn't work in type position
bbrk24 opened this issue · comments
With coffeePrototype, T::# works as an expression but not a type.
Does T.prototype.length actually make sense? T.foo is a namespace dereference, so I don't think there's any sense of prototype chain.
In type position, T::length currently compiles to T["length"].
Oops, right, I see.