我在使用的时候遇到的输入输出的问题

[Joaus]

我在使用winpwn测试本地的可执行程序的时候，出现了以下的问题

1.返回的pid为0

2. 无法接收打开的进程的输出，自然也无法写入，事实上我也不知道到底有没有创建进程成功，因为上面返回的pid是0

我的测试程序代码如下：
`#include <stdio.h>
#include <windows.h>
#include
#include
using namespace std;
int main()
{
setbuf(stdout,0);
setbuf(stdin,0);
setbuf(stderr,0);

cout << "Hello  welcome To winpwn Test\nPlease input your luckey number\n";
int number;
while(1)
{
    cin >> number;
    if(number == 99)
    {

        system("cmd");
    }
    else{
        cout << "try again!"<< endl;
    }
}
return 1;

}
我写的python脚本：# -- coding: utf-8 --
"""
Created on Fri Aug 14 21:58:01 2020

@author: 美好的一天
"""
from winpwn import *

context.log_level = 'debug'
context.arch = 'amd64'

p = process("D:\Program Files (x86)\CodeBlocks\Project\test.exe")
#sleep(10)
#p.recvuntil("Please input your luckey number\n")
print(p.recvall())

p.sendline('99')
p.interactive()`

在使用recvall的时候会一直停留在recv这里
`runfile('E:/CTF/PythonScripts/WinpwnTest.py', wdir='E:/CTF/PythonScripts')

+: Create process success #pid 0x0

而在我不使用recv直接sendline的报错就是这样
` runfile('E:/CTF/PythonScripts/WinpwnTest.py', wdir='E:/CTF/PythonScripts')

+: Create process success #pid 0x0
<bound method tube.recv of <winpwn.winpwn.process object at 0x00000216C941B5C0>>

0000 39 39 0d 0a |99..
Traceback (most recent call last):

File "", line 1, in
runfile('E:/CTF/PythonScripts/WinpwnTest.py', wdir='E:/CTF/PythonScripts')

File "E:\anaconda\lib\site-packages\spyder_kernels\customize\spydercustomize.py", line 668, in runfile
execfile(filename, namespace)

File "E:\anaconda\lib\site-packages\spyder_kernels\customize\spydercustomize.py", line 108, in execfile
exec(compile(f.read(), filename, 'exec'), namespace)

File "E:/CTF/PythonScripts/WinpwnTest.py", line 18, in
p.sendline('99')

File "E:\anaconda\lib\site-packages\winpwn\winpwn.py", line 40, in sendline
return self.send(buf+newline)

File "E:\anaconda\lib\site-packages\winpwn\winpwn.py", line 34, in send
showbuf(buf)

File "E:\anaconda\lib\site-packages\winpwn\misc.py", line 141, in showbuf
os.write(sys.stdout.fileno(), Latin1_encode(buf))

UnsupportedOperation: fileno`

[Joaus]

解决了，首先我的可执行文件路径写的是Windows风格的。然后是fileno这个问题直接用命令行去执行就不会有报错，用spyder去执行就会有这个报错，很迷。。